lt;br>$A\cos\left( \omega t+\phi-\frac{\pi}{2} \right)=A\sin(\omega t+\phi)$ | ### Relative Phase Shift > [!figure] ![[Relative phase shift 1.png]] > © University of Southampton [^1] These two signals are both sinusoidal, which the same frequency, so we can write: $ x_{1}(t)=A_{1}\cos(\omega t+\phi_{1}) \qquad x_{2}(t)=A_{2}\cos(\omega t+\phi_{2}) $ The phase difference, or relative phase (shift), between $x_{1}(t)$ and $x_{2}(t)$ is: $ \Delta\phi=\phi_{2}-\phi_{1} $ ### Lead and Lag > [!figure] ![[Angular frequency.png]] > © University of Southampton [^1] We have two sinusoidal signals: $ x_{1}(t)=A_{1}\cos(\omega t+\phi_{1}) \qquad x_{2}(t)=A_{2}\cos(\omega t+\phi_{2}) $ Depending on the difference between the phase of the two signals, we can say: | Rules | Terminology | | ----------------------------------------------------------- | ------------------------------------------------------------------ | | $\phi_{2}-\phi_{1}=0$ | $x_{1}(t)$ and $x_{2}(t)$ are **in phase** | | $\phi_{2}-\phi_{1}<\pi$ then $\Delta\phi=\phi_{2}-\phi_{1}$ | $x_{2}(t)$ **leads** $x_{1}(t)$ by $\Delta\phi$ | | $\phi_{2}-\phi_{1}=\pi$ | $x_{2}(t)$ is in **antiphase** or **out of phase** with $x_{1}(t)$ | | $\phi_{2}-\phi_{1}>\pi$ | Swap, and use other rules | ### Velocity and Acceleration A mass undergoing SHM has displacement $y(t)$ from equilibrium given by $x(t)=A\cos(\omega t+\phi)$. Its velocity $v(t)$ is the. rate of the change of its displacement with time, so: $ v(t)=\dot{x}(t)=\frac{dx}{dt}=-\omega A\sin(\omega t+\phi) $ Since $-\sin(\omega t+\phi)=\cos\left( \omega t+\phi+\frac{\pi}{2} \right)$, this tells us that its velocity leads its displacement by $90^{\circ}$. Its acceleration $a(t)$ is the rate of change of its velocity with time, so: $ a(t)=\dot{v}(t)=\ddot{x}(t)=\frac{dv}{dt}=\frac{d^2x}{d^2t}=-\omega^2A\cos(\omega t+\phi) $ The acceleration is in anti-phase to the displacement, and lags the velocity by $90^{\circ}$. The acceleration is always in the opposite direction to the displacement. When the displacement-magnitude is the greatest: - The velocity is zero - The acceleration-magnitude is greatest When the mass passes through its equilibrium position: - The magnitude of the velocity is the greatest - The acceleration is zero TODO: vibration week 2 ## Speed and reflection Reminder of concepts from vibrations: - Frequency $f$ and period $T$ are reciprocals - Natural frequency $f_{n}$ depends on restoring force and inertia - Angular frequency $\omega$ is the rate of change of phase (angle) with time - Kinetic and potential energy are exchanged as the system vibrates $ f=\frac{1}{T}=\frac{\omega}{2\pi}=\frac{1}{2\pi}\sqrt{ \frac{k}{m} } $ ### Speed of mechanical waves Wave-bearing media have inertia and restoring force, as do vibrating systems. Mechanical waves transport energy without transporting matter. As with vibration, the energy is in kinetic and potential forms. In a progressive wave, the kinetic and potential energies travel together (rather than exchanging). In strings, the restoring force comes from tension $\tau$ and the mass per unit length $\micro$ to give: $ c=\sqrt{ \frac{\tau}{\micro} } $ #### Speed of sound In a fluid, the inertia comes from its density $\rho_{0}$. The restoring force comes from its bulk modulus, $B_{0}$, the reciprocal of its compressibility. The speed of sound therefore is: $ c=\sqrt{ \frac{B_{0}}{\rho_{0}} } $ In liquids, both are large. In gasses, both are small. Generally, sound travels faster in liquids and slower in gases, but as it is due to the ratio it is by no means guaranteed. There are some gases which have a faster speed of sound than some liquids. In an ideal gas, such as air, $B_{0}=\gamma P_{0}$ where $\gamma=\frac{C_{p}}{C_{V}}$ is the adiabatic index of the gas (about 1.4 for air). The ideal gas law states that $P=\rho RT$ where $R$ is the gas constant and $T$ is absolute temperature. Speed of sound is therefore: $ c=\sqrt{ \frac{B_{0}}{\rho_{0}} }=\sqrt{ \frac{\gamma P_{0}}{\rho_{0}} }=\sqrt{ \frac{\gamma\rho_{0}RT_{0}}{\rho_{0}} }=\sqrt{ \gamma RT_{0} } $ It is proportional to the square root of absolute temperature. At room temperature it is about $341\text{ m s}^{-1}$ and increases by about $0.6\ m$ for each $^{\circ}\text{C}$ of temperature rise. #### Speed in solids Solids can support both longitudinal and transverse waves. They're called 'P waves' and 'S waves' (primary and secondary). Because the restoring force is different, they travel at different speeds. For bending waves (aka flexural waves) in plates and beams, the restoring force depends on: - Stiffness of the material - Thickness - Curvature of the bend ### Superposition Most mechanical waves, at small enough amplitudes, obey the principle of superposition. This states that waves pass through one another without affecting each other. Mathematically this means that if we have expressions for individual waves, we can just add them together. TODO: finish vibration week 3 ## Standing Waves and Modes Single-frequency saves are sinusoidal in both space and time. Their wavelength (spatial period) is related to their frequency (reciprocal of temporal period) by $c=f\lambda$. When a wave meets boundaries that arrest its motion, a reflected wave is generated with opposing direction of propagation and opposing (inverted) motion. For longitudinal waves (such as sound waves) the pressure in the reflected wave is not inverted. ### Standing waves on semi-infinite strings A single-frequency wave qave reflects from the fixed end of a semi-infinite string. Superimposing a positive and a negative-going wave with the same amplitude and wavelength creates a standing wave. Unlike the progressive (travelling) wave, energy is exchanged between kinetic and potential forms. Every half-wavelength from the fixed end the dispalcement vanishes. We call these points displacement nodes. Displacement antinodes occur in between displacement nodes. On a semi-infinite string, stranding waves can satisfy the boundary condition at any frequency. ### Standing waves on finite strings > [!figure] ![[Standing waves on finite strings.gif]] > © University of Southampton [^1] Consider a finite string of length $L$, fixed at both ends. Only certain single-frequency waves will satisfy the boundary conditions at both ends. At those frequencies, the ends of the string much be a whole number of half-wavelengths apart, e.g: $ L=n\frac{\lambda}{2}\qquad n=1,2,\dots $ This will be true at a set of wavelengths $\lambda_{n}=2\frac{L}{2}$ At those frequencies, since $c=f_{n}\lambda_{n}$ $ f_{n}=\frac{c}{\lambda_{n}}=\frac{nc}{2L} $ We call $f_{1}$ the fundamental - it's the note the string is tuned to. #### Worked example The A-string of a guitar is 63 cm long, weighs 2.5 grammes, and is tuned to 110 Hz; what is it's tension? **What do we know?** - Fundamental frequency is related to length by $f_{1}=\frac{c}{2L}$ - Wave-speed is related to tension by $c=\sqrt{ \frac{\tau}{\micro} }$ - Mass per unit length is related to mass and length by $\micro=\frac{m}{L}$ - We know $m$, $L$ and $f_{1}$ - We want to find $\tau$ Combine the equations: $ \tau=uc^2=\left( \frac{m}{L} \right)\times(2f_{1}L)^2=4f_{1}^2mL $ Substitute values: $ \tau=4f_{1}^2mL=4\times 110^2 \times 0.0025 \times 0.63=76.2N $ ### Standing acoustic waves ![[Standing acoustic waves.gif]] Superimposing a positive-going wave and a negative going wave of the same frequency and amplitude creates a standing acoustic wave. The regions where the pressure exactly cancels out are pressure nodes, half a wavelength apart. Pressure nodes are velocity antinodes and vice versa. Hard-wall boundary conditions L m apart are satisfied when $f_{n}=\frac{nc}{2L}$ as before. What is $n$ for the case shown? ### Frequency > [!figure] ![[Frequency ranges.png]] > © University of Southampton [^1] - Nominal range of human hearing is $20\text{ Hz to } 20\text{ kHz}$ - Infrasound lt;20\text{ Hz}$ - Ultrasound (A) $17.8\text{ to } 500 \text{ kHz}$ can cause acoustic cavitation in liquids or body tissue - Ultrasound (B) $500\text{ kHz to } 100\text{ MHz}$ can cause temperature rise in tissue - Ultrasound (C) gt;100\text{ MHz}$ can generate radiation forces ### Pitch > [!figure] ![[Pitch.png]] > © University of Southampton [^1] A fixed pitch difference corresponds to a fixed fequency ratio. If the pitch of $f_{2}$ is an octave above $f_{1}$ then $\frac{f_{2}}{f_{1}}=2$. In the Equal Temperament (ET) tuning system, octaves are divided into 12 equal semitones. In the Scientific Pitch Notation (SPN) notes are specified a name C-B followed by the number of the octave it occurs inas shown above. ISO16 specifies A4 (yellow) as $440\text{ Hz}$ (often called concert pitch). We call the lowest modal frequency of a pipe or string its fundamental $f_{1}$. We call $f_{n}$ the $(n-1)\text{th}$ overtone of the pipe or string. ### Standing waves and modes [^1]: https://blackboard.soton.ac.uk/bbcswebdav/pid-7789956-dt-content-rid-37918172_1/xid-37918172_1?xythos-download=true